1
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The maximum number of points of intersection of 10 circles is :

A
80
B
90
C
85
D
95
2
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

$${{{C_1}} \over {{C_0}}} + 2{{{C_2}} \over {{C_1}}} + 3{{{C_3}} \over {{C_2}}} + 4{{{C_4}} \over {{C_3}}} + ....20{{{C_{20}}} \over {{C_{19}}}} = $$

A
120
B
260
C
210
D
180
3
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1
If p$$\ne$$ q $$\ne$$ r and $$\left| {\matrix{ 0 & {x - p} & {x - q} \cr {x + p} & 0 & {x - r} \cr {x + q} & {x - r} & 0 \cr } } \right| = 0$$, then the value of x which satisfy the equation is
A
x = p
B
x = q
C
x = r
D
x = 0
4
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

Matrix $$A = \left| {\matrix{ x & 3 & 2 \cr 1 & y & 4 \cr 2 & 2 & z \cr } } \right|$$, if xyz = 60 and 8x + 4y + 3z = 20, then A(adj A) is equal to

A
$$\left[ {\matrix{ {64} & 0 & 0 \cr 0 & {64} & 0 \cr 0 & 0 & {64} \cr } } \right]$$
B
$$\left[ {\matrix{ {88} & 0 & 0 \cr 0 & {88} & 0 \cr 0 & 0 & {88} \cr } } \right]$$
C
$$\left[ {\matrix{ {68} & 0 & 0 \cr 0 & {68} & 0 \cr 0 & 0 & {68} \cr } } \right]$$
D
$$\left[ {\matrix{ {34} & 0 & 0 \cr 0 & {34} & 0 \cr 0 & 0 & {34} \cr } } \right]$$
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