1
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The value of $$\mathop {\lim }\limits_{x \to 0} {{\sqrt {1 - {{\cos x}^2}} } \over {1 - \cos x}}$$ is

A
$${1 \over 2}$$
B
2
C
$$\sqrt 2 $$
D
None of these
2
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

If $$f(x) = \left\{ {\matrix{ {a{x^2} + 1,} & {x \le 1} \cr {{x^2} + ax + b,} & {x > 1} \cr } } \right.$$ is differentiable at x = 1, then

A
a = 1, b = 1
B
a = 1, b = 0
C
a = 2, b = 0
D
a = 2, b = 1
3
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The slope of the tangent to the curve x = t2 + 3t $$-$$ 8, y = 2t2 $$-$$ 2t $$-$$ 5 at the point t = 2 is

A
$${7 \over 6}$$
B
$${5 \over 6}$$
C
$${6 \over 7}$$
D
1
4
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

$$\int {{1 \over {1 - 2\sin x}}dx} $$ is equal to

A
$${1 \over {2\sqrt 3 }}\log \left| {{{\tan {x \over 2} - 2 - \sqrt 3 } \over {\tan {x \over 2} - 2 + \sqrt 3 }}} \right| + c$$
B
$${{\sqrt 3 } \over 2}\log \left| {{{\tan {x \over 2} - 2 - \sqrt 3 } \over {\tan {x \over 2} - 2 + \sqrt 3 }}} \right| + c$$
C
$${1 \over {\sqrt 3 }}\log \left| {{{\tan {x \over 2} - 2 - \sqrt 3 } \over {\tan {x \over 2} - 2 + \sqrt 3 }}} \right| + c$$
D
None of the above
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