1
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \cos 13^{\circ} \sin 17^{\circ} \sin 21^{\circ} \cos 47^{\circ}= $$

A

$\frac{1}{32}(1+\sqrt{2}-\sqrt{3})$

B

$\frac{1}{16}(1+\sqrt{3}+\sqrt{5})$

C

$\frac{1}{16}(2+\sqrt{3}-\sqrt{5})$

D

$\frac{1}{32}(1+2 \sqrt{3}-\sqrt{5})$

2
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$$ \sin \frac{\pi}{5}+\sin \frac{2 \pi}{5}+\sin \frac{3 \pi}{5}+\sin \frac{4 \pi}{5}= $$
A

1

B

$\sqrt{5}$

C

$\frac{1}{4}(\sqrt{5}+1)(\sqrt{10+2 \sqrt{5}})$

D

$\frac{1}{4}(\sqrt{5}-1)(\sqrt{10+2 \sqrt{5}})$

3
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The sum of the solutions of $\cos x \sqrt{16 \sin ^2 x}=1$ in $(0,2 \pi)$ is
A

$2 \pi$

B

$\frac{13 \pi}{2}$

C

$\frac{17 \pi}{4}$

D

$4 \pi$

4
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $\cot \left(\cos ^{-1} x\right)=\sec \left\{\tan ^{-1}\left(\frac{a}{\sqrt{b^2-a^2}}\right)\right\}, b>a$ then $x=$

A

$\frac{b}{\sqrt{2 b^2-a^2}}$

B

$\frac{a}{\sqrt{2 b^2-a^2}}$

C

$\frac{\sqrt{b^2-a^2}}{a}$

D

$\frac{\sqrt{b^2-a^2}}{b}$