1
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For $0 < x < 1, \int\left[\tan ^{-1}\left(1-x+x^2\right)+\tan ^{-1}(1-x)\right] d x=$

A

$x \cot ^{-1} x+\log \sqrt{1+x^2}+C$

B

$x \tan ^{-1} x-\log \left(1+x^2\right)+C$

C

$x \cot ^{-1} x+\frac{3}{4} \log \left(1+x^2\right)+C$

D

$x \tan ^{-1} x-\frac{3}{4} \log \sqrt{1+x^2}+C$

2
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_{-2 \pi}^{2 \pi} \sin ^4(2 x) \cos ^6(2 x) d x= $$

A

$\frac{3 \pi}{64}$

B

$\frac{9 \pi}{64}$

C

$\frac{9 \pi}{35}$

D

$\frac{9 \pi}{280}$

3
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $f(t)=\int_0^t \tan ^{(2 n-1)} x d x, n \in N$, then $f(t+\pi)=$

A

$f(t) f(\pi)$

B

$f(t)-f(\pi)$

C

$f(t)+f(\pi)$

D

$\frac{f(t)}{f(\pi)}$

4
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^2 x^8\left(\frac{4}{x^2}-1\right)^{\frac{5}{2}} d x= $$

A

$\frac{2^{15}}{63}$

B

$\frac{2^{16}}{315}$

C

$\frac{2^{16}}{189}$

D

$\frac{2^{10}}{63}$