1
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^2 x^8\left(\frac{4}{x^2}-1\right)^{\frac{5}{2}} d x= $$

A

$\frac{2^{15}}{63}$

B

$\frac{2^{16}}{315}$

C

$\frac{2^{16}}{189}$

D

$\frac{2^{10}}{63}$

2
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The area (in sq. units) of the region bounded by the curves $y=x^2$ and $y=8-x^2$ is

A

$\frac{32}{3}$

B

$\frac{16}{3}$

C

$\frac{64}{3}$

D

$\frac{128}{3}$

3
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The solution of the differential equation $x^2(y+1) \frac{d y}{d x}+y^2(x+1)^2=0$, when $y(1)=2$, is

A

$\log \left|x^2 y\right|=\frac{2}{x}+\frac{1}{y}+x-1$

B

$\log \left|\frac{1}{4} x^2 y\right|=\frac{1}{x}+\frac{2}{y}+x-1$

C

$\log \left|\frac{1}{2} x^2 y\right|=\frac{1}{x}+\frac{1}{y}-x-\frac{1}{2}$

D

$\log \left|\frac{1}{3} x^2 y\right|=\frac{1}{x}+\frac{1}{y}-x+\frac{1}{2}$

4
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the differential equation $\frac{d y}{d x}=\frac{2 x+y-3}{2 y-x+3}$

A

$x^2-x y-y^2+3 x+3 y+c=0$

B

$x^2-x y-y^2-3 x-3 y+c=0$

C

$x^2+x y-y^2-3 x-3 y+c=0$

D

$x^2+x y+y^2+3 x-3 y+c=0$