$$ \int \frac{d x}{(x+1) \sqrt{x^2+1}}= $$
$\frac{1}{\sqrt{2}} \sinh ^{-1}\left(\frac{1+x}{1-x}\right)+C$
$\frac{1}{\sqrt{2}} \sinh ^{-1}\left(\frac{1-x}{1+x}\right)+C$
$-\frac{1}{\sqrt{2}} \sinh ^{-1}\left(\frac{1-x}{1+x}\right)+C$
$-\frac{1}{\sqrt{2}} \sinh ^{-1}\left(\frac{1+x}{1-x}\right)+C$
If $\int \frac{d x}{2 \cos x+3 \sin x+4}=\frac{2}{\sqrt{3}} f(x)+C$, then $f\left(\frac{2 \pi}{3}\right)=$
$\frac{\pi}{12}$
$\frac{\pi}{8}$
$\frac{5 \pi}{12}$
$\frac{5 \pi}{8}$
If $\int \frac{1}{\left((x+4)^3(x+1)^5\right)^{1 / 4}} d x=A \cdot\left(\frac{x+4}{x+1}\right)^n+C$
$n$ A=3
$n+\frac{1}{A}=-\frac{1}{2}$
$A+n=1$
$A=n$
$$ \int_{-\pi / 2}^{\pi / 2} \sin ^2 x \cos ^2 x(\sin x+\cos x) d x= $$
0
$\frac{2}{15}$
$\frac{4}{15}$
$\frac{2}{5}$
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