1
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\cos \theta=\frac{-3}{5}$ and $\theta$ does not lie in second quadrant, then $\tan \frac{\theta}{2}=$

A

2

B

1

C

-2

D

-1

2
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution satisfying both the equations $\sin x=-\frac{3}{5}$ and $\cos x=-\frac{4}{5}$ is

A

$x=(2 n+1) \pi+\tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

B

$x=2 n \pi+\tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

C

$x=n \pi+\tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

D

$x=n \pi \pm \tan ^{-1}\left(\frac{3}{4}\right), n \in Z$

3
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The number of solution of $\tan ^{-1} 1+\frac{1}{2} \cos ^{-1} x^2-\tan ^{-1} \left(\frac{\sqrt{1+x^2}+\sqrt{1-x^2}}{\sqrt{1+x^2}-\sqrt{1-x^2}}\right)=0$ is

A

3

B

0

C

1

D

infinitely many

4
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \tanh ^{-1}(\sin \theta)= $$

A

$\sinh ^{-1}(\operatorname{cosec} \theta)$

B

$\sinh ^{-1}(\sec \theta)$

C

$\cosh ^{-1}(\operatorname{cosec} \theta)$

D

$\cosh ^{-1}(\sec \theta)$