1
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equation of the curve passing through the point $(0, \pi)$ and satisfying the differential equation $y d x=\left(x+y^3 \cos y\right) d y$ is

A

$x=y^2 \sin y+y \cos ^2 y$

B

$x=y^2 \sin y+2 y \cos ^2 \frac{y}{2}$

C

$x=y^2 \sin y+y \cos ^2 \frac{y}{2}$

D

$x=y^2 \sin y-y \cos ^2 y$

2
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the differential equation $(x-(x+y) \log (x+y)) d x+x d y=0$ is

A

$y \log (x+y)=c x$

B

$\log (x+y)=c y$

C

$x \log (x+y)=c y$

D

$\log (x+y)=c x$

3
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the equation for the velocity of a particle at time ' $t$ ' is $v=$ at $+\frac{b}{t+c}$, then the dimensions of $a, b, c$ are respectively

A

$\left[\mathrm{LT}^{-2}\right],[\mathrm{L}],[\mathrm{T}]$

B

$\left[\mathrm{L}^2\right],[\mathrm{L}],[\mathrm{T}]$

C

$\left[\mathrm{LT}^{-2}\right],[\mathrm{LT}],[\mathrm{L}]$

D

$[\mathrm{L}],[\mathrm{LT}],\left[\mathrm{L}^2\right]$

4
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If a stone thrown vertically upwards from a bridge with an initial velocity of $5 \mathrm{~ms}^{-1}$, strikes the water below the bridge in a time of 3 s , then the height of the bridge above the water surface is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
A

10 m

B

26 m

C

30 m

D

18 m