$$ \int_0^{\pi / 4} \frac{\cos ^2 x}{\cos ^2 x+4 \sin ^2 x} d x= $$
$\frac{\pi}{2}-\frac{1}{3} \tan ^{-1} 2$
$-\frac{\pi}{4}-\frac{4}{3} \tan ^{-1} 2$
$\frac{\pi}{6}+\frac{2}{3} \tan ^{-1} 2$
$-\frac{\pi}{12}+\frac{2}{3} \tan ^{-1} 2$
$$ \int_{5 \pi}^{25 \pi}|\sin 2 x+\cos 2 x| d x= $$
$20 \sqrt{2}$
$10 \sqrt{2}$
$40 \sqrt{2}$
$80 \sqrt{2}$
The differential equation of the family of circles passing through the origin and having centre on $X$-axis is
$\left(y^2+x^2\right) d x-2 y d y=0$
$\left(y^2-x^2\right) d x-2 x y d y=0$
$\left(y^2-x^2\right) d x+2 y d y=0$
$\left(y^2+x^2\right) d x+2 y d y=0$
The general solution of the differential equation $\frac{d y}{d x}=\frac{x+y}{x-y}$ is
$y-x=c x^2$
$\tan ^{-1}\left(\frac{y}{x}\right)=\log \left(c x \sqrt{x^2+y^2}\right)$
$x+y=c x^2$
$\tan ^{-1}\left(\frac{y}{x}\right)=\log \left(c \sqrt{x^2+y^2}\right)$
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