$$ \int\left(\sum_{r=0}^{\infty} \frac{x^r 2^r}{r!}\right) d x= $$
$e^x+C$
$\frac{-2}{1-2 x}+C$
$2 e^{2 x}+C$
$\frac{e^{2 x}}{2}+C$
$$ \int \frac{d x}{12 \cos x+5 \sin x}= $$
$\frac{1}{13} \log \left|\tan \left(\frac{\pi}{4}+\frac{x}{2}-\frac{1}{2} \tan ^{-1} \frac{5}{12}\right)\right|+C$
$\frac{5}{12} \log \left|\tan \left(\frac{\pi}{4}+\frac{x}{2}-\frac{1}{2} \tan ^{-1} \frac{5}{12}\right)\right|+C$
$\frac{1}{13} \log \left|\tan \left(\frac{\pi}{4}+\frac{x}{2}+\frac{1}{2} \tan ^{-1} \frac{5}{12}\right)\right|+C$
$\frac{5}{12} \log \left|\tan \left(\frac{\pi}{4}+\frac{x}{2}+\frac{1}{2} \tan ^{-1} \frac{5}{12}\right)\right|+C$
If $\int \frac{\cos ^3 x}{\sin ^2 x+\sin ^4 x} d x=c-\operatorname{cosec} x-f(x)$, then $f\left(\frac{\pi}{2}\right)=$
1
0
$\pi / 2$
$\pi$
$$ \int \frac{13 \cos 2 x-9 \sin 2 x}{3 \cos 2 x-4 \sin 2 x} d x= $$
$3 x-\frac{1}{2} \log |3 \cos 2 x-4 \sin 2 x|+C$
$\frac{x}{2}-3 \log |3 \cos 2 x-4 \sin 2 x|+C$
$3 x+\frac{1}{2} \log |3 \cos 2 x-4 \sin 2 x|+C$
$x+\frac{3}{2} \log |3 \cos 2 x-4 \sin 2 x|+C$
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