$$ \int \frac{13 \cos 2 x-9 \sin 2 x}{3 \cos 2 x-4 \sin 2 x} d x= $$
$3 x-\frac{1}{2} \log |3 \cos 2 x-4 \sin 2 x|+C$
$\frac{x}{2}-3 \log |3 \cos 2 x-4 \sin 2 x|+C$
$3 x+\frac{1}{2} \log |3 \cos 2 x-4 \sin 2 x|+C$
$x+\frac{3}{2} \log |3 \cos 2 x-4 \sin 2 x|+C$
$$ \int \sqrt{x^2+x+1} d x $$
$\frac{(2 x+1)}{4} \sqrt{x^2+x+1}+\frac{3}{8} \sinh ^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+C$
$\frac{x+1}{4} \sqrt{x^2+x+1}+\frac{3}{8} \sinh ^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+C$
$\frac{x+1}{4} \sqrt{x^2+x+1}-\frac{3}{8} \sinh ^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+C$
$\frac{(2 x+1)}{4} \sqrt{x^2+x+1}-\frac{3}{8} \sinh ^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+C$
If $k \in N$, then $\lim\limits_{n \rightarrow \infty}\left[\frac{1}{n+1}+\frac{1}{n+2}+\frac{1}{n+3}+\ldots .+\frac{1}{k n}\right]=$
$\log (k+1)$
$\log k$
$\log (k+5)$
$\log (k+1)-\log 6$
$$ \int_{-1}^4 \sqrt{\frac{4-x}{x+1}} d x= $$
0
$\frac{\pi}{2}$
$\frac{3 \pi}{2}$
$\frac{5 \pi}{2}$
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