1
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The general solution of $\cot \frac{x}{2}-\cot x=\operatorname{cosec} \frac{x}{2}$ is
A
$\left\{\left.2 n \pi+\frac{\pi}{3} \right\rvert\, n \in z\right\}$
B
$\left\{\left.4 n \pi+\frac{\pi}{3} \right\rvert\, n \in z\right\}$
C
$\left\{\left.2 n \pi+\frac{2 \pi}{3} \right\rvert\, n \in z\right\}$
D
$\left\{\left.4 n \pi \pm \frac{2 \pi}{3} \right\rvert\, n \in z\right\}$
2
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $0 < x < \frac{1}{2}$ and $\alpha=\sin ^{-1} x+\cos ^{-1}\left(\frac{x}{2}+\frac{\sqrt{3-3 x^2}}{2}\right)$, then $\tan \alpha+\cot \alpha$ is equal to

A
$\frac{4}{\sqrt{3}}$
B
$4 \sqrt{3}$
C
$\frac{4 x}{1-x^2}$
D
$x \sqrt{1-x^2}$
3
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\cosh (\log 4)$ is equal to
A
$\frac{8}{17}$
B
$\frac{17}{8}$
C
0
D
$\frac{9}{8}$
4
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In $\triangle A B C, a^2 \sin 2 B+b^2 \sin 2 A$ is equal to
A
$2 a b \cos A$
B
$2 a b \sin A$
C
$2 \mathrm{ab} \sin \mathrm{C}$
D
$2 a b \cos C$
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