1
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The moment of inertia of a solid sphere about its diameter is $20 \mathrm{~kg}-\mathrm{m}^2$. The moment of inertia of a thin spherical shell having the same mass and radius about its diameter is
A
$16.6 \mathrm{~kg}-\mathrm{m}^2$
B
$30.3 \mathrm{~kg}-\mathrm{m}^2$
C
$33.3 \mathrm{~kg}-\mathrm{m}^2$
D
$66.6 \mathrm{~kg}-\mathrm{m}^2$
2
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
One ring, one solid sphere and one solid cylinder are rolling down on same inclined plane starting from rest The radius of all the three are equal. The object reaches down with maximum velocity is
A
solid cylinder
B
solid sphere
C
ring
D
solid sphere and ring
3
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

As shown in the figure, two blocks of masses $m_1$ and $m_2$ are connected to spring of force constant $k$. The blocks are slightly displaced in opposite directions to $x_1, x_2$ distances and released. If the system executes simple harmonic motion, then the frequency of oscillation of the system ( $\omega$ ) is

AP EAPCET 2024 - 23th May Morning Shift Physics - Simple Harmonic Motion Question 1 English
A
$\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k^2$
B
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k^2}$
C
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right)}$
D
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k}$
4
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A mass $M$, attached to a horizontal spring executes simple harmonic motion with amplitude $A_1$. When mass $M$ passes mean position, then a smaller mass millis attached to it and both of them together executing simple harmonic motion with amplitude $A_2$. Then, value of $\frac{A_1}{A_2}$ is
A
$\sqrt{\frac{m^2+M^2}{M^2}}$
B
$\sqrt{\frac{m+M}{M^2}}$
C
$\sqrt{\frac{m+M}{M}}$
D
$$ \text { } \frac{m+M}{M} $$
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