MHT CET (PCB) 2024 22th April Evening Shift | Fluid Mechanics Question 3 | Physics

Water rises up to height ' $x$ ' in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth 'd' in a mine, the water level rises height ' $Y$ '. If ' $R$ ' is the radius of earth then the ratio $(\mathrm{Y} / \mathrm{x})$ is

$\frac{2 R}{(R-d)}$

$\frac{\mathrm{R}^2}{(\mathrm{R}-\mathrm{d})}$

$\frac{\mathrm{R}}{(\mathrm{R}-\mathrm{d})}$

$\frac{\mathrm{R}}{(\mathrm{R}+\mathrm{d})}$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

Water is flowing through a horizontal pipe in a streamline flow. At the narrowest part of the pipe

velocity is maximum and pressure is minimum.

pressure is maximum and velocity is minimum.

both the pressure and velocity are minimum.

both the pressure and velocity are maximum.

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

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Work done to get ' $n$ ' spherical drops of equal size from a single spherical drop of water, is proportional to

$\left(\frac{1}{\mathrm{n}^{2 / 3}}-1\right)$

$\left(\frac{1}{\mathrm{n}^{1 / 3}}-1\right)$

$n^{1 / 3}-1$

$\mathrm{n}^{4 / 3}-1$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

A light metal disc of radius ' $r$ ' floats on water surface and bends the surface downwards along the perimeter making an angle ' $\theta$ ' with the vertical edge of the disc. If the weight of water displaced by the disc is ' W ', the weight of the metal disc is [ $\mathrm{T}=$ surface tension of water]

$\quad \mathrm{W}-2 \pi \mathrm{r} \mathrm{T} \cos \theta$

$2 \pi r \mathrm{~T}+\mathrm{W}$

$2 \pi \mathrm{r} \mathrm{T} \cos \theta+\mathrm{W}$

$2 \pi \mathrm{rT} \cos \theta-\mathrm{W}$

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