MHT CET (PCB) 2024 22th April Evening Shift | Heat and Thermodynamics Question 5 | Physics

Rate of flow of heat through a cylindrical rod is $\mathrm{H}_1$. The temperature of the ends of the rod are ' $\mathrm{T}_1$ ' and ' $\mathrm{T}_2$ '. If all the dimensions of the rod become double and the temperature difference remains the same, the rate of flow of heat becomes ' $\mathrm{H}_2$ '. Then $\mathrm{H}_2=$

$\frac{\mathrm{H}_1}{2}$

$\quad 2 \mathrm{H}_1$

$\frac{\mathrm{H}_{\mathrm{t}}}{4}$

$4 \mathrm{H}_1$

MHT CET (PCB) 2024 22th April Evening Shift

MCQ (Single Correct Answer)

-0

For which of the following combinations of working temperatures, the efficiency of Carnot's engine is maximum?

40 K and 20 K

50 K and 30 K

70 K and 50 K

90 K and 60 K

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

Two stars 'A' and 'B' radiate maximum energy at $5200 \mathop {\rm{A}}\limits^ \circ$ and $6500 \mathop {\rm{A}}\limits^ \circ$ respectively. Then the ratio of absolute temperatures of stars ' A ' and ' $B$ ' is $$\mathop {\rm{A}}\limits^ \circ $$

$25: 16$

$5: 4$

$4: 5$

$16: 25$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

A spherical body of radius ' $r$ ' radiates power ' $P$ ' at $T$ kelvin. If the radius $s$ halved and the temperature doubled the power radiated in the same time ' t ' will be

$\frac{\mathrm{P}}{2}$

2 P

4 P

8 P

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