MHT CET (PCB) 2024 22th April Evening Shift | Ray Optics Question 3 | Physics

A thin concavo-convex lens with convex face receiving incident rays has radii of curvatures 12 cm and 24 cm respectively. If refractive index of material of lens is 1.5 , then the focal length of the lens is

16 cm

24 cm

32 cm

48 cm

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

When a ray of light is refracted from one medium to another, then the wavelength changes from $6000 \mathop {\rm{A}}\limits^ \circ$ to $4000 \mathop {\rm{A}}\limits^ \circ$. The critical angle for the interface will be

$\cos ^{-1}\left(\frac{3}{2}\right)$

$\sin ^{-1}\left(\frac{2}{\sqrt{3}}\right)$

$\sin ^{-1}\left(\frac{2}{3}\right)$

$\cos ^{-1}\left(\frac{2}{\sqrt{3}}\right)$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

For a given medium, the speed of light and the polarising angle are ' $v$ ' and ' $i_p$ ' respectively, then ( $\mathrm{c}=$ speed of light in vaccum )

$\quad v \sin \left(\mathrm{i}_{\mathrm{p}}\right)=c \cos \left(\mathrm{i}_{\mathrm{p}}\right)$

$\quad \mathrm{c}=\mathrm{v} \cot \left(\mathrm{i}_{\mathrm{p}}\right)$

$\quad v \cos \left(\mathrm{i}_{\mathrm{p}}\right)=c \sin \left(\mathrm{i}_{\mathrm{p}}\right)$

$\quad v=c \cos \left(i_p\right)$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

A transparent sphere of refractive index ' $\mu$ ' and radius of curvature ' $R$ ' is kept in air. A point object is placed at a distance ' d ' from the surface of the sphere so that the real image is formed at the same distance ' $d$ ' from exactly opposite side of the sphere. The distance ' $d$ ' is

$\frac{\mu}{R}$

$\mathrm{R}(\mu-1)$

$\frac{\mathrm{R}}{(\mu-1)}$

$\frac{\mathrm{R}}{(\mu+1)}$

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