1
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A bicycle wheel of diameter ' $D$ ' has ' $N$ ' number of spokes. Wheel is rotating at the rate of ' $x$ ' revolutions per minute, perpendicular to the horizontal component of earth's magnetic field ' $\mathrm{B}_{\mathrm{H}}$ '. The e.m.f. induced between the rim and the centre of the wheel will be

A

$\frac{\mathrm{B}_{\mathrm{H}} \pi \mathrm{Dx}}{120}$

B

$\quad \frac{\mathrm{B}_{\mathrm{H}} \pi \mathrm{Dx}}{240}$

C

$\frac{B_H \pi D^2 x}{240}$

D

$\quad \frac{\mathrm{B}_{\mathrm{H}} \pi \mathrm{D}^2 \mathrm{x}}{120}$

2
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

If current ' i ' is passing through the solenoid of diameter ' $d$ ' having number of turns per unit length ' $n$ ', then the inductance per unit length near the middle of a long solenoid is directly proportional to

A

d and n

B

$\mathrm{d}^2$ and n

C

d and $\mathrm{n}^2$

D

$\mathrm{d}^2$ and $\mathrm{n}^2$

3
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

The flux linked with the coil at any instant ' t ' is given by $\phi=12 t^2-60 t+275$. The magnitude of induced e.m.f. at $\mathrm{t}=3 \mathrm{~second}$ is

A
200 V
B
108 V
C
72 V
D
12 V
4
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A coil of area $12 \mathrm{~cm}^2$ has 250 turns. Magnetic field of $0.2 \mathrm{~Wb} / \mathrm{m}^2$ is perpendicular to the plane of the coil. The field is reduced to $0.1 \mathrm{~Wb} / \mathrm{m}^2$ in 0.1 second. The magnitude of induced e.m.f. in the coil is

A
0.2 V
B
0.3 V
C
3 V
D
6 V

MHT CET (Biology) Subjects

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