An air capacitor of plate area ' $A$ ' and separation between the plates is ' $d$ ' has a capacity ' $C$ '. Two dielectric slabs are inserted between its plates in two different manners as shown in figure. The capacitance of a capacitor is

$\frac{\varepsilon_0 A}{d-\frac{t_1}{k_1}+\frac{t_2}{k_2}}$
$\frac{\varepsilon_0 A}{d+t_1+t_2+\frac{t_1}{k_1}+\frac{t_2}{k_2}}$
$\frac{\varepsilon_0 A}{d-t_1-t_2+\frac{t_1}{k_1}+\frac{t_2}{k_2}}$
$\frac{\varepsilon_0 A}{d+t_1+t_2-\frac{t_1}{k_1}-\frac{t_2}{k_2}}$
The output Y of a given logic circuit is (For inputs $\mathrm{A}, \mathrm{B}$ and C )

$\quad \mathrm{Y}=\overline{\mathrm{A}} \cdot(\overline{\mathrm{B}+\mathrm{C}})$
$\mathrm{Y}=(\overline{\mathrm{A} \cdot \mathrm{B}})+(\overline{\mathrm{B} \cdot \mathrm{C}})$
$ \mathrm{Y}=(\overline{\mathrm{A}+\mathrm{B}}) \cdot(\overline{\mathrm{B}+\mathrm{C}})$
$Y=(A+B) \cdot C$
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