Two (A and B) pendulums begin to swing simultaneously. The first pendulum (A) makes five oscillations when the other (B) makes three oscillations. The ratio of the lengths of pendulum $A$ to that of $B$ is
$3: 5$
$9: 25$
$5: 3$
$2: 3$
Two identical photocathodes receive light of frequencies ' $f 1$ ' and ' $f_2$ '. The velocity of the photoelectrons of mass ' $m$ ' emitted are respectively ' $\mathrm{v}_1$ ' and ' $\mathrm{v}_2$ '. Then the correct relation is ( $\mathrm{h}=$ Planck's constant)
$\quad v_1-v_2=\left[\frac{2 h}{m}\left(f_1-f_2\right)\right]^{\frac{1}{2}}$
$\quad v_1+v_2=\left[\frac{2 h}{m}\left(f_1+f_2\right)\right]^{\frac{1}{2}}$
$v_1^2-v_2^2=\frac{2 h}{m}\left(f_1-f_2\right)$
$v_1^2+v_2^2=\frac{2 h}{m}\left(f_1+f_2\right)$
The capacitive reactance of a capacitor connected to 50 V d.c. is
zero.
$10 \Omega$.
$50 \Omega$.
infinity.
A particle performs S.H.M. with amplitude 'A'. The speed of the particle is $\left(\frac{1}{3}\right)^{\text {rd }}$ of the maximum speed when its displacement from the mean position is
$\frac{\mathrm{A}}{3}$
$\frac{\sqrt{2} \mathrm{~A}}{3}$
$\frac{2 \sqrt{2} \mathrm{~A}}{3}$
$\frac{2 \mathrm{~A}}{3}$
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