A uniform metal wire has length ' $L$ ', mass ' $M$ ' and area of cross-section ' A '. It is under tension ' $T$ ' and ' $V$ ' is the speed of transverse wave along the wire. The density of the wire is
$\quad \mathrm{TV}^2 \mathrm{~A}$
$\frac{\mathrm{T}}{\mathrm{V}^2 \mathrm{~A}}$
$\frac{\mathrm{A}}{\mathrm{TV}^2}$
$\frac{\mathrm{V}^2}{\mathrm{AT}}$
The main difference in the working of a step-up transformer and CE amplifier is
the transformer decreases the power whereas the amplifier keeps the power constant.
the transformer increases the power whereas the amplifier decreases the power.
the amplifier increases the power but the transformer can not increase the power.
the amplifier decreases the power but the transformer keeps the power constant.
A particle of mass 0.02 kg executes S.H.M. about $\mathrm{x}=0$ under the influence of a force as shown in figure. The period of S.H.M. is

$\frac{\pi}{5} \mathrm{~s}$
$\frac{\pi}{10} \mathrm{~s}$
$\pi \mathrm{s}$
$\frac{\pi}{20} \mathrm{~s}$
The current $I$ is flowing through a loop $A B C D A$ as shown in the figure. The magnitude of the magnetic field at the centre ' $O$ ' is $x$ times
$$ \left(\frac{\mu_0 \mathrm{I}}{\mathrm{R}}\right)\left(\mathrm{OD}=\mathrm{R}, \mathrm{DC}=\mathrm{R}, \angle \mathrm{AOD}=90^{\circ}\right) $$
The value of ' $x$ ' is ( $\mu_0=$ permeability of free space)

$\frac{5}{16}$
$\frac{5}{12}$
$\frac{7}{16}$
$\frac{7}{12}$
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