For a wire $$\frac{R}{\ell}=\frac{1}{2}$$ and length of wire is $$\ell=5 \mathrm{~cm}$$. If potential difference of $$\mathrm{l} \mathrm{V}$$ is applied across it, then current through wire will be ($$R=$$ Resistance)
If modulation index, $$\mu=\frac{1}{2}$$ and $$V_m=2$$, then $$V_C$$ is
A body of mass $$5 \times 10^3 \mathrm{~kg}$$ moving with speed $$2 \mathrm{~m} / \mathrm{s}$$ collides with a body of mass $$15 \times 10^3 \mathrm{~kg}$$ inelastically and sticks to it. Then loss in $$\mathrm{KE}$$ of the system will be
If focal length of objective and eye lenses are $$10 \mathrm{~cm}$$ and $$10 \mathrm{~mm}$$ respectively and tube length is $$11 \mathrm{~cm}$$ then angular magnification of telescope is
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