A capacitor of capacitance $$15 \mu \mathrm{F}$$ having dielectric slab of $$\varepsilon_r=2.5$$, dielectric strength $$30 \mathrm{~MV} / \mathrm{m}$$ and potential difference $$=30 \mathrm{~V}$$. Calculate the area of the plate.
For a wire $$\frac{R}{\ell}=\frac{1}{2}$$ and length of wire is $$\ell=5 \mathrm{~cm}$$. If potential difference of $$\mathrm{l} \mathrm{V}$$ is applied across it, then current through wire will be ($$R=$$ Resistance)
If modulation index, $$\mu=\frac{1}{2}$$ and $$V_m=2$$, then $$V_C$$ is
A body of mass $$5 \times 10^3 \mathrm{~kg}$$ moving with speed $$2 \mathrm{~m} / \mathrm{s}$$ collides with a body of mass $$15 \times 10^3 \mathrm{~kg}$$ inelastically and sticks to it. Then loss in $$\mathrm{KE}$$ of the system will be