1
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The line $y-\sqrt{3} x+3=0$ cuts the parabola $y^2=x+2$ at the points $P$ and $Q$. If the co-ordinates of the point $X$ are $(\sqrt{3}, 0)$, then the value of $X P \cdot X Q$ is

A
$\frac{4(2+\sqrt{3})}{3}$
B
$\frac{4(2-\sqrt{3})}{2}$
C
$\frac{5(2+\sqrt{3})}{3}$
D
$\frac{5(2-\sqrt{3})}{3}$
2
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let $f(x)=|1-2 x|$, then

A
$f(x)$ is continuous but not differentiable at $x=\frac{1}{2}$.
B
$f(x)$ is differentiable but not continuous at $x=\frac{1}{2}$.
C
$f(x)$ is both continuous and differentiable at $x=\frac{1}{2}$.
D
$f(x)$ is neither differentiable nor continuous at $x=\frac{1}{2}$.
3
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If ' $f$ ' is the inverse function of ' $g$ ' and $g^{\prime}(x)=\frac{1}{1+x^n}$, then the value of $f^{\prime}(x)$ is

A
$1+\{f(x)\}^n$
B
$1-\{f(x)\}^n$
C
$\{1+f(x)\}^n$
D
$\{f(x)\}^n$
4
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If the matrix $\left(\begin{array}{ccc}0 & a & a \\ 2 b & b & -b \\ c & -c & c\end{array}\right)$ is orthogonal, then the values of $a, b, c$ are

A
$a= \pm \frac{1}{\sqrt{3}}, b= \pm \frac{1}{\sqrt{6}}, c= \pm \frac{1}{\sqrt{2}}$
B
$a= \pm \frac{1}{\sqrt{2}}, b= \pm \frac{1}{\sqrt{6}}, c= \pm \frac{1}{\sqrt{3}}$
C
$a=-\frac{1}{\sqrt{2}}, b=-\frac{1}{\sqrt{6}}, c=-\frac{1}{\sqrt{3}}$
D
$a=\frac{1}{\sqrt{3}}, b=\frac{1}{\sqrt{6}}, c=\frac{1}{\sqrt{3}}$
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