1
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
Let P be the foot of the perpendicular from focus S of hyperbola $${{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1$$ on the line bx $$-$$ ay = 0 and let C be the centre of the hyperbola. Then, the area of the rectangle whose sides are equal to that of SP and CP is
A
2ab
B
ab
C
$${{({a^2} + {b^2})} \over 2}$$
D
$${a \over b}$$
2
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
B is an extremity of the minor axis of an ellipse whose foci are S and S'. If $$\angle SBS'$$ is a right angle, then the eccentricity of the ellipse is
A
$${1 \over 2}$$
B
$${1 \over {\sqrt 2 }}$$
C
$${2 \over 3}$$
D
$${1 \over 3}$$
3
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The axis of the parabola $${x^2} + 2xy + {y^2} - 5x + 5y - 5 = 0$$ is
A
$$x + y = 0$$
B
$$x + y - 1 = 0$$
C
$$x - y + 1 = 0$$
D
$$x - y = {1 \over {\sqrt 2 }}$$
4
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The line segment joining the foci of the hyperbola $${x^2} - {y^2} + 1 = 0$$ is one of the diameters of a circle. The equation of the circle is
A
$${x^2} + {y^2} = 4$$
B
$${x^2} + {y^2} = \sqrt 2 $$
C
$${x^2} + {y^2} = 2$$
D
$${x^2} + {y^2} = 2\sqrt 2 $$
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