A mass $M$ is broken into two parts of masses $m_1$ and $m_2$. How are $m_1$ and $m_2$ related, so that force of gravitational attraction between the two parts is maximum?
$m_1=\frac{M}{6}, m_2=\frac{5 M}{6}$
$m_1=\frac{M}{3}, m_2=\frac{2 M}{3}$
$m_1=\frac{M}{4}, m_2=\frac{3 M}{4}$
$m_1=\frac{M}{2}, m_2=\frac{M}{2}$
The frequency of a light wave in a material is $2 \times 10^{14} \mathrm{~Hz}$ and wavelength is $5000 \mathop {\rm{A}}\limits^{\rm{o}} $. The refractive index of material will be
1.40
1.50
3.00
1.33
A man with a mass of 80 kg is standing on the rim to a circular platform with a mass of 200 kg . The circular platform is rotating at 12 revolutions per minute (rpm) about its axis. The man moves from the rim towards the centre of the platform. The new angular velocity of the system will be (Assuming that the man's moment of inertia at the centre of the plateform is negligible)
10 rpm
12 rpm
21.6 rpm
zero
Two wires of the same material (Young's modulus $=Y$ ) and same length $L$ but radii $R$ and $2 R$ respectively are joined end to end and a weight $w$ is suspended from the combination as shown in the figure. The elastic potential energy in the system is

$\frac{3 w^2 L}{4 \pi R^2 Y}$
$\frac{3 w^2 L}{8 \pi R^2 Y}$
$\frac{5 w^2 L}{8 \pi R^2 Y}$
$\frac{w^2 L}{\pi R^2 Y}$
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