A string of length $L$ and force constant $k$ is stretched to obtain extension $l$. It is further stretched to obtain extension $l_1$. The work done in second stretching is
$\frac{1}{2} k l_1\left(2 l+l_1\right)$
$\frac{1}{2} k l_1^2$
$\frac{1}{2} k\left(l^2+l_1^2\right)$
$\frac{1}{2} k\left(l_1^2-l^2\right)$
A block of mass 10 kg slides down a rough slope which is inclined at an angle of $45^{\circ}$ to the horizontal. The coefficient of sliding friction is 0.30 . When the block has slide 5 m , the work done on the block by the force of friction is nearly
115 J
$-75 \sqrt{2} \mathrm{~J}$
321.4 J
-321.4 J
In a Young's double slit experiment for a particular wavelength of light the distance between third dark and fifth bright fringe is 1.63 mm . If the distance between two slit is 1 mm and distance between slit and screen is 1 metre. Then, the wavelength of light is
$5.5 \times 10^{-7} \mathrm{~m}$
$6 \times 10^{-7} \mathrm{~m}$
$6.5 \times 10^{-7} \mathrm{~m}$
$7.5 \times 10^{-7} \mathrm{~m}$
A mass $M$ is broken into two parts of masses $m_1$ and $m_2$. How are $m_1$ and $m_2$ related, so that force of gravitational attraction between the two parts is maximum?
$m_1=\frac{M}{6}, m_2=\frac{5 M}{6}$
$m_1=\frac{M}{3}, m_2=\frac{2 M}{3}$
$m_1=\frac{M}{4}, m_2=\frac{3 M}{4}$
$m_1=\frac{M}{2}, m_2=\frac{M}{2}$
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