1
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

$$ \text { The value of } \lim _\limits{x \rightarrow 0} \frac{(27+x)^{1 / 3}-3}{9-(27+x)^{2 / 3}} \text { equals to } $$

A
$$-\frac{1}{3}$$
B
$$\frac{1}{6}$$
C
$$-\frac{1}{6}$$
D
$$\frac{1}{3}$$
2
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

If a tangent to the circle $$x^2+y^2=1$$ intersect the co-ordinate axes at distinct points $$P$$ and $$Q$$, then the locus of the mid-point of $$P Q$$ is

A
$$x^2+y^2-2 x y=0$$
B
$$x^2+y^2-2 x^2 y^2=0$$
C
$$x^2+y^2-4 x^2 y^2=0$$
D
$$x^2+y^2-16 x^2 y^2=0$$
3
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

Let $$f(x)=\int \frac{\sqrt{x}}{(1+x)^2} d x$$, where $$x \geq 0$$. Then, $$f(3)-f(1)$$ is equal to

A
$$\frac{\pi}{12}+\frac{1}{2}-\frac{\sqrt{3}}{4}$$
B
$$-\frac{\pi}{6}+\frac{1}{2}+\frac{\sqrt{3}}{4}$$
C
$$-\frac{\pi}{12}+\frac{1}{2}+\frac{\sqrt{3}}{4}$$
D
$$\frac{\pi}{6}+\frac{1}{2}-\frac{\sqrt{3}}{4}$$
4
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

The mean and variance of the data $$4,5,6,6,7,8, x, y$$, where $$x< y$$ are 6 and $$\frac{9}{4}$$, respectively. Then, $$x^2-2 y$$ is equal to

A
8
B
32
C
0
D
4
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