$P(-1)$ is not minimum of $P(x)$, but $P(1)$ is the maximum of $P(x)$

$P(-1)$ is minimum of $P(x)$, but $P(1)$ is not the maximum of $P(x)$

Neither $P(-1)$ is the minimum nor $P(1)$ is the maximum of $P(x)$

$P(-1)$ is the minimum and $P(1)$ is the maximum of $P(x)$

2

3

4

6

$b, d, a, c$

b, a, c, d

$a, b, c, d$

$b, a, d, c$

$\frac{1}{3} \log \left(\frac{x+1}{x^2+x+1}\right)+C$

$\frac{1}{3} \log \left(\frac{(x-1)^2}{x^2+x+1}\right)+C$

$\frac{1}{3} \log \left(\frac{x-1}{x^2+x+1}\right)+C$

$\frac{1}{3} \log \left(\frac{(x+1)^2}{x^2-x+1}\right)+C$