1
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If a function,

$$ f(x)=\left\{\begin{array}{cc} \frac{\sqrt[3]{1+a x^2+b x^3}-\sqrt[3]{1-a x^2-b x^3}}{x^2}, & x<0 \\ 5, & x=0 \\ \frac{\tan 3 x-\sin 3 x}{b x^3}, & x>0 \end{array}\right. $$

is continuous at $x=0$, then the geometric mean of $a$ and $b$ is

A

$\frac{3}{2}$

B

$\frac{9}{2}$

C

$\frac{81}{4}$

D

$\frac{9}{4}$

2
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\log \left(\sec \left(\tan ^{-1} x\right)\right)(x>0)$, then $\frac{d y}{d x}$ at $x=1$ is

A

1

B

3

C

$\frac{1}{2}$

D

$\frac{3}{2}$

3
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\sin ^{-1} \frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}}$ and $\frac{-3 \pi}{2}

A

$-\frac{\left|\operatorname{cosec} \frac{x}{2}\right|}{2 \sqrt{\sin ^2 \frac{x}{2}-\cos ^2 \frac{x}{2}}}$

B

$\frac{\left|\sec \frac{x}{2}\right|}{2 \sqrt{\cos x}}$

C

$\frac{\cos \frac{x}{2}}{2 \sqrt{\cos x}}$

D

$\frac{\cos \frac{x}{2}}{\sqrt{\cos x}}$

4
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $x=\sqrt{2} e^t(\sin t-\cos t)$ and $y=\sqrt{2} e^t(\sin t+\cos t)$, then $\left(\frac{d^2 y}{d x^2}\right)_{t=\frac{\pi}{4}}=$

A

$-e^{\frac{-\pi}{4}}$

B

$\sqrt{2} e^{\frac{\pi}{4}}$

C

$\sqrt{2} e^{\frac{-\pi}{4}}$

D

$e^{\frac{-\pi}{4}}$