1
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The number of ways of distributing 3 dozen fruits (no two fruits are identical) to 9 persons such that each gets the same number of fruits is

A

$\frac{36!}{(9!)^4}$

B

$\frac{36!}{(4!)^9}$

C

${ }^{36} P_9 \times 4$ !

D

$\frac{36!}{4!(9!)^4}$

2
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\binom{p}{q}={ }^p C_q$ and $\sum\limits_{i=0}^m\binom{10}{i}\binom{20}{m-i}$ is maximum, then $m=$

A

10

B

12

C

15

D

20

3
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Coefficient of $x^2$ in the expansion of $\left(x^2+x-2\right)^5$ is

A

800

B

756

C

0

D

512

4
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $P_n$ denotes the product of the binomial coefficients in the expansion of $(1+x)^n$, then $\frac{P_{n+1}}{P_n}=$

A

$\frac{n+1}{n!}$

B

$\frac{n^n}{n!}$

C

$\frac{(n+1)^n}{(n+1)!}$

D

$\frac{(n+1)^{n+1}}{(n+1)!}$