1
AP EAPCET 2024 - 21th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A rectangular loop of sides 25 cm and 10 cm carrying a current of 10 A is placed with its longer side parallel to a long straight conductor 10 cm apart carrying current 25 A . The net force on the loop is
A
$6.25 \times 10^{-5} \mathrm{~N}$
B
$5.5 \times 10^{-5} \mathrm{~N}$
C
$3.75 \times 10^{-5} \mathrm{~N}$
D
$8.75 \times 10^{-11} \mathrm{~N}$
2
AP EAPCET 2024 - 21th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the vertical component of the earth's magnetic field is 0.45 G at a location and angle of dip is $60^{\circ}$, then magnetic field of earth in that location is
A
0.26 G
B
0.52 G
C
0.3 G
D
0.7 G
3
AP EAPCET 2024 - 21th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$X$ and $Y$ are two circuits having coefficient of mutual inductance 3 mH and resistance $10 \Omega$ and $4 \Omega$ respectively. To have induced current $60 \times 10^{-4} \mathrm{~A}$ in circuit $Y$, the amount of current to be changed in circuit $X$ in 0.02 s is
A
1.6 A
B
0.16 A
C
0.32 A
D
3.2 A
4
AP EAPCET 2024 - 21th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two figures are shown as Fig. $A$ and Fig. $B$. The time constant of Fig. $A$ is $\tau_A$ and time constant of Fig. $B$ is $\tau_B$. Then AP EAPCET 2024 - 21th May Morning Shift Physics - Capacitor Question 1 English
A
$\tau_A=\frac{1}{4} \mathrm{~s}$ and $\tau_B=5 \mathrm{~s}$
B
$\tau_A=\frac{1}{2} \mathrm{~s}$ and $\tau_B=\frac{1}{5} \mathrm{~s}$
C
$\tau_A=4 \mathrm{~s}$ and $\tau_B=5 \mathrm{~s}$
D
$\tau_A=\frac{1}{3} \mathrm{~s}$ and $\tau_B=10 \mathrm{~s}$
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