1
CBSE 12th Math (Term 1) Paper 2021-22
MCQ (Single Correct Answer)
+1
-0
In a sphere of radius r, a right circular cone of height h having maximum curved surface area is inscribed. The expression for the square of curved surface of cone is
A
$$2{\pi ^2}rh(2rh + {h^2})$$
B
$${\pi ^2}hr(2rh + {h^2})$$
C
$$2{\pi ^2}r(2r{h^2} - {h^3})$$
D
$$2{\pi ^2}{r^2}(2rh - {h^2})$$
2
CBSE 12th Math (Term 1) Paper 2021-22
MCQ (Single Correct Answer)
+1
-0
The corner points of the feasible region determined by a set of constraints (linear inequalities) are P(0, 5), Q(3, 5), R(5, 0) and S(4, 1) and the objective function is Z = ax + 2by where a, b > 0. The condition on a and b such that the maximum Z occurs at Q and S is
A
a $$-$$ 5b = 0
B
a $$-$$ 3b = 0
C
a $$-$$ 2b = 0
D
a $$-$$ 8b = 0
3
CBSE 12th Math (Term 1) Paper 2021-22
MCQ (Single Correct Answer)
+1
-0
If curves y2 = 4x and xy = c cut at right angles, then the value of c is
A
$$4\sqrt 2 $$
B
8
C
$$2\sqrt 2 $$
D
$$-$$$$4\sqrt 2 $$
4
CBSE 12th Math (Term 1) Paper 2021-22
MCQ (Single Correct Answer)
+1
-0
The inverse of the matrix $$X = \left[ {\matrix{ 2 & 0 & 0 \cr 0 & 3 & 0 \cr 0 & 0 & 4 \cr } } \right]$$ is
A
$$24\left[ {\matrix{ {1/2} & 0 & 0 \cr 0 & {1/3} & 0 \cr 0 & 0 & {1/4} \cr } } \right]$$
B
$${1 \over {24}}\left[ {\matrix{ 1 & 0 & 0 \cr 0 & 1 & 0 \cr 0 & 0 & 1 \cr } } \right]$$
C
$${1 \over {24}}\left[ {\matrix{ 2 & 0 & 0 \cr 0 & 3 & 0 \cr 0 & 0 & 4 \cr } } \right]$$
D
$$\left[ {\matrix{ {1/2} & 0 & 0 \cr 0 & {1/3} & 0 \cr 0 & 0 & {1/4} \cr } } \right]$$
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