If $|\vec{A} \times \vec{B}|=\sqrt{3}(\vec{A} \cdot \vec{B})$ then the value of $|\vec{A}+\vec{B}|$ is $\left(\tan 60^{\circ}=\sqrt{3}, \cos 60^{\circ}=0.5\right)$
$\left(A^2+B^2+\frac{A B}{\sqrt{3}}\right)^{\frac{1}{2}}$
$\left(A^2+B^2+A B\right)^{\frac{1}{2}}$
$\left(A^2+B^2+\sqrt{3} A B\right)^{\frac{1}{2}}$
$\mathrm{A}+\mathrm{B}$
In an interference experiment, the phase difference between the waves reaching a first dark point is
zero
$\pi^{\mathrm{c}}$
$\left(\frac{3 \pi}{2}\right)^{\mathrm{c}}$
$(2 \pi)^c$
The magnetic field at the centre of a current carrying circular coil of area ' $A$ ' is ' $B$ '. The magnetic moment of the coil is $x$ times $\left(2 B / \mu_0\right)$. The value of $x$ is ( $\mu_0=$ permeability of free space)
$\left(\frac{\mathrm{A}}{\pi^2}\right)^{\frac{1}{3}}$
$\left(\frac{\pi^3}{A^3}\right)^{\frac{1}{2}}$
$\left(\frac{\pi^2}{\mathrm{~A}^2}\right)^{\frac{1}{3}}$
$\left(\frac{A^3}{\pi}\right)^{\frac{1}{2}}$
A capacitor of capacitance ' C ' is connected across a.c. source of voltage V as $\mathrm{V}=\mathrm{V}_0 \sin \omega \mathrm{t}$. The displacement current between the plates of the capacitor would be
$V_0 \omega C \cos \omega t$
$\frac{V_0}{\omega C} \sin \omega t$
$\frac{V_0}{\omega C} \cos \omega t$
$\mathrm{V}_0 \omega \mathrm{C} \sin \omega \mathrm{t}$
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