1
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two spherical black bodies of radius $\mathrm{R}_1$ and $\mathrm{R}_2$ with surface temperatures $\mathrm{T}_1$ and $\mathrm{T}_2$ respectively. If $T_1=2 T_2$ and they radiate the same power then relation between $R_1$ and $R_2$ is

A

$R_2=8 R_1$

B

$\mathrm{R}_2=\mathrm{R}_1$

C

$R_2=2 R_1$

D

$R_2=4 R_1$

2
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum has mass 2 gram and charge $2 \mu \mathrm{C}$. In a uniform horizontal electric field of intensity $1000 \mathrm{~V} / \mathrm{m}$, pendulum is at rest. At equilibrium, the angle made by the pendulum with the vertical is ( $\mathrm{g}=$ acceleration due to gravity $=10 \mathrm{~m} / \mathrm{s}^2$ )

A

$\tan ^{-1}(0.2)$

B

$\tan ^{-1}(0.1)$

C

$\tan ^{-1}(0.4)$

D

$\tan ^{-1}(0.5)$

3
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A mass ' $M$ ' is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes S.H.M. of periodic time ' $T$ '. If the mass is increased by ' $m$ ', the time period becomes $4 T / 3$, then the ratio of $\frac{\mathrm{M}}{\mathrm{m}}$ is

A

$3: 1$

B

$9: 7$

C

$7: 9$

D

$1: 3$

4
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The energy of a photon is equal to the kinetic energy of proton. If $\lambda_1$ is the de-Broglie wavelength of a proton, $\lambda_2$ is the wavelength associated with the photon and if E is the energy of photon then $\lambda_2: \lambda_1$ is

A

$1: \sqrt{3 \mathrm{E}}$

B

$1: \sqrt{E}$

C

$\sqrt{\mathrm{E}}: 1$

D

$\sqrt{3 E}: 1$