1
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A thin concavo-convex lens with convex face receiving incident rays has radii of curvatures 12 cm and 24 cm respectively. If refractive index of material of lens is 1.5 , then the focal length of the lens is

A
16 cm
B
24 cm
C
32 cm
D
48 cm
2
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

At two points on a horizontal tube of varying cross-section the radii are 1 cm and $\mathbf{0 . 4 ~ c m}$, velocities of fluid are $\mathrm{V}_1, \mathrm{~V}_2$ and pressure difference ( $P_1-P_2$ ) between these points is 4.9 cm of water. The value of $\sqrt{V_2^2-V_1^2}$ is ( $\mathrm{g}=$ acceleration due to gravity $\mathrm{g}=980 \mathrm{~cm} / \mathrm{s}^2$ )

A
$9.8 \mathrm{~cm} / \mathrm{s}$
B
$98 \mathrm{~cm} / \mathrm{s}$
C
$980 \mathrm{~cm} / \mathrm{s}$
D
$0.98 \mathrm{~cm} / \mathrm{s}$
3
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A simple harmonic progressive wave is given by equation $y=\operatorname{asin} 2 \pi\left(n t-\frac{x}{\lambda}\right)$. If the wave velocity is equal to $\frac{1}{4} \times$ (maximum particle velocity), then the wavelength ' $\lambda$ ' is (Given $\rightarrow \mathrm{a}=$ amplitude, $\mathrm{n}=$ frequency, $\mathrm{t}=$ time, $\mathrm{y}=$ displacement, $\mathrm{x}=$ distance )

A
$\frac{\pi \mathrm{a}}{2}$
B
$\pi a$
C
$\frac{4}{\pi a}$
D
$\frac{4 \pi}{\mathrm{a}}$
4
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { In the following figure, the current } \mathrm{I} \text { is equal to } $$

MHT CET (PCB) 2024 22th April Evening Shift Physics - Current Electricity Question 1 English

A
4.5 A
B
6.2 A
C
7.8 A
D
9.5 A
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