1
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

If $A=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]$ and $B=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right]$, then $\left(B B^T A\right)^5$ is equal to

A
$\left[\begin{array}{cc}2+\sqrt{3} & 1 \\ -1 & 2-\sqrt{3}\end{array}\right]$
B
$\frac{1}{2}\left[\begin{array}{ll}1 & 5 \\ 0 & 1\end{array}\right]$
C
$\left[\begin{array}{ll}1 & 5 \\ 0 & 1\end{array}\right]$
D
$\left[\begin{array}{ll}5 & 1 \\ 0 & 1\end{array}\right]$
2
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

The value of ' $a$ ' for which the lines $\frac{x-2}{1}=\frac{y-9}{2}=\frac{z-13}{3}$ and $\frac{x-a}{-1}=\frac{y-7}{2}$ $=\frac{z+2}{-3}$ intersect, is

A
$-5$
B
$-2$
C
$5$
D
$-3$
3
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

The length of three sides of a trapezium are equal, each being 10 cms . Then, the maximum area $\left(\mathrm{cm}^2\right)$ of the trapezium is

A
$75 \sqrt{2}$
B
$50 \sqrt{2}$
C
$50 \sqrt{3}$
D
$75 \sqrt{3}$
4
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

If $(\cos x)^y=(\sin y)^x$, then $\frac{d y}{d x}$ equals

A
$\frac{\log \sin y-y \tan x}{\log \cos x+x \cot y}$
B
$\frac{\log \sin y+y \tan x}{\log \cos x-x \cot y}$
C
$\frac{\log \sin y+y \tan x}{\log \cos x+x \cot y}$
D
$\frac{\log \sin y+y \tan x}{\log \cos y-y \cot x}$
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