1
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

If $e$ is the eccentricity of hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ and $\theta$ is the angle between the asymptotes, then $\cos \frac{\theta}{2}$ is

A
$\frac{1}{e}$
B
$\frac{1}{\sqrt{e}}$
C
$-\frac{1}{e}$
D
$\frac{1}{\sqrt{e^2+2}}$
2
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

If tangent to the curve $f(x)=x^3-\alpha x^2-x+\beta$ at point $(1,3)$ on the curve, cut equals non zero intercepts on co-ordinate axes, then

A
$\alpha+\beta=6$
B
$\alpha-\beta=3$
C
$\alpha \beta=27$
D
$\frac{\beta}{\alpha}=6$
3
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

The sum of $1+\frac{1}{4}+\frac{1 \cdot 3}{4 \cdot 8}+\frac{1 \cdot 3 \cdot 5}{4 \cdot 8 \cdot 12}+\ldots \infty$ is

A
$\sqrt{3}$
B
$\frac{1}{\sqrt{2}}$
C
$\sqrt{2}$
D
$2^{\frac{3}{2}}$
4
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

A short bar magnet of magnetic moment of $0.15 \mathrm{~J} / \mathrm{T}$ is placed in a uniform magnetic field of 0.4 T . The potential energy of the magnet in unstable equilibrium is

A
$6 \times 10^{-4} \mathrm{~J}$
B
$-6 \times 10^{-2} \mathrm{~J}$
C
$6 \times 10^{-2} \mathrm{~J}$
D
$-6 \times 10^{-4} \mathrm{~J}$
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