1
VITEEE 2022
MCQ (Single Correct Answer)
+1
-0

The image of the point $$(2,-3,4)$$ with respect to the plane $$4 x+2 y-4 z+3=0$$, is

A
$$\left(\frac{-16}{9}, \frac{14}{9}, \frac{40}{9}\right)$$
B
$$\left(\frac{40}{9}, \frac{-16}{9}, \frac{14}{9}\right)$$
C
$$\left(\frac{14}{9}, \frac{-16}{9}, \frac{40}{9}\right)$$
D
$$\left(\frac{40}{9}, \frac{14}{9}, \frac{-16}{9}\right)$$
2
VITEEE 2022
MCQ (Single Correct Answer)
+1
-0

If a variable plane cuts the coordinate axes in $$A, B, C$$ and is at constant distance $p$ from the origin, then the locus of the centroid of the tetrahedron $$A B C$$ is equal to

A
$$x^{-2}+y^{-2}+z^{-2}=16 p^2$$
B
$$x^{-2}+y^{-2}+z^{-2}=8 p^2$$
C
$$x^{-2}+y^{-2}+z^{-2}=16 p^{-2}$$
D
$$x^{-2}+y^{-2}+z^{-2}=8 p^{-2}$$
3
VITEEE 2022
MCQ (Single Correct Answer)
+1
-0

If the tangent at $$P$$ on $$y^2=4 a x$$ meets the tangent at the vertex in $$Q$$ and $$S$$ is the focus of the parabola, then $$\angle S Q P$$ is equal to

A
$$\frac{\pi}{3}$$
B
$$\frac{\pi}{4}$$
C
$$\frac{\pi}{2}$$
D
$$\frac{2 \pi}{3}$$
4
VITEEE 2022
MCQ (Single Correct Answer)
+1
-0

For all values of $$\lambda$$, rank of matrix

$$A=\left[\begin{array}{ccc} { }^h C_0 & { }^4 C_3 & { }^5 C_4 \\ \lambda & 8 & 8 \lambda-6 \\ 1+\lambda^2 & 8 \lambda+4 & 2 \lambda+21 \end{array}\right]$$

A
for $$\lambda=2, \rho(A)=1$$
B
for $$\lambda=-1, \rho(A)=1$$
C
for $$\lambda=2, \rho(A)=3$$
D
for $$\lambda=-1, \rho(A)=4$$
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