1
KCET 2022
MCQ (Single Correct Answer)
+1
-0

If $$e^y+x y=e$$ the ordered pair $$\left(\frac{d y}{d x}, \frac{d^2 y}{d x^2}\right)$$ at $$x=0$$ is equal to

A
$$\left(\frac{1}{e}, \frac{1}{e^2}\right)$$
B
$$\left(\frac{-1}{e}, \frac{-1}{e^2}\right)$$
C
$$\left(\frac{1}{e}, \frac{-1}{e^2}\right)$$
D
$$\left(\frac{-1}{e}, \frac{1}{e^2}\right)$$
2
KCET 2022
MCQ (Single Correct Answer)
+1
-0

$$\int \frac{\cos 2 x-\cos 2 \alpha}{\cos x-\cos \alpha} d x$$ is equal to

A
$$2(\sin x-x \cos \alpha)+c$$
B
$$2(\sin x+x \cos \alpha)+c$$
C
$$2(\sin x-2 x \cos \alpha)+c$$
D
$$2(\sin x+2 x \cos \alpha)+c$$
3
KCET 2022
MCQ (Single Correct Answer)
+1
-0

$$\int_0^1 \frac{x e^x}{(2+x)^3} d x$$ is equal to

A
$$\frac{1}{27} \cdot e-\frac{1}{8}$$
B
$$\frac{1}{27} \cdot e+\frac{1}{8}$$
C
$$\frac{1}{9} \cdot e+\frac{1}{4}$$
D
$$\frac{1}{9} \cdot e-\frac{1}{4}$$
4
KCET 2022
MCQ (Single Correct Answer)
+1
-0

If $$\int \frac{d x}{(x+2)\left(x^2+1\right)}=a \log \left|1+x^2\right|+b \tan ^{-1} x +\frac{1}{5} \log |x+2|+c,$$ then

A
$$a=\frac{-1}{10}, b=\frac{2}{5}$$
B
$$a=\frac{1}{10}, b=\frac{2}{5}$$
C
$$a=\frac{-1}{10}, b=\frac{-2}{5}$$
D
$$a=\frac{1}{10}, b=\frac{-2}{5}$$
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