1
KCET 2022
MCQ (Single Correct Answer)
+1
-0

Let the relation $$R$$ is defined in $$N$$ by $$a R b$$, if $$3 a+2 b=27$$ then $$R$$ is

A
$$\{(1,12)(3,9)(5,6)(7,3)\}$$
B
$$\left\{\left(0, \frac{27}{2}\right)(1,12)(3,9)(5,6)(7,3)\right\}$$
C
$$\{(1,12)(3,9)(5,6)(7,3)(9,0)\}$$
D
$$\{(2,1)(9,3)(6,5)(3,7)\}$$
2
KCET 2022
MCQ (Single Correct Answer)
+1
-0

$$\lim _\limits{y \rightarrow 0} \frac{\sqrt{3+y^3}-\sqrt{3}}{y^3}=$$

A
$$\frac{1}{2 \sqrt{3}}$$
B
$$\frac{1}{3 \sqrt{2}}$$
C
$$2 \sqrt{3}$$
D
$$3 \sqrt{2}$$
3
KCET 2022
MCQ (Single Correct Answer)
+1
-0

If $$A$$ is a matrix of order $$3 \times 3$$, then $$\left(A^2\right)^{-1}$$ is equal to

A
$$\left(-A^2\right)^2$$
B
$$\left(A^{-1}\right)^2$$
C
$$A^2$$
D
$$(-A)^{-2}$$
4
KCET 2022
MCQ (Single Correct Answer)
+1
-0

If $$A=\left[\begin{array}{ll}2 & -1 \\ 3 & -2\end{array}\right]$$, then the inverse of the matrix $$A^3$$ is

A
A
B
$$-1$$
C
1
D
$$-A$$
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