1
COMEDK 2021
MCQ (Single Correct Answer)
+1
-0

If $${(\sqrt 3 + i)^{100}} = {2^{99}}(a + ib)$$, then $${a^2} + {b^2}$$ is equal to

A
$$\sqrt2$$
B
4
C
$$\sqrt3$$
D
None of these
2
COMEDK 2021
MCQ (Single Correct Answer)
+1
-0

Using mathematical induction, the numbers $${a_n}$$'s are defined by $${a_0} = 1,{a_{n + 1}} = 3{n^2} + n + {a_n},(n \ge 0)$$. Then, $${a_n}$$ is equal to

A
$${n^3} + {n^2} + 1$$
B
$${n^3} - {n^2} + 1$$
C
$${n^3} - {n^2}$$
D
$${n^3} + {n^2}$$
3
COMEDK 2021
MCQ (Single Correct Answer)
+1
-0

If $$49^n+16n+P$$ is divisible by 64 for all $$n\in N$$, then the least negative integral value of P is

A
$$-2$$
B
$$-3$$
C
$$-4$$
D
$$-1$$
4
COMEDK 2021
MCQ (Single Correct Answer)
+1
-0

$${2^{3n}} - 7n - 1$$ is divisible by

A
64
B
36
C
49
D
25
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