If $\int \frac{5 \tan x}{\tan x-2} d x=a x+b \log |\sin x-2 \cos x|+c$, then $a+b=$
2
3
4
-1
$$ \int x \cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right) d x(x>0)= $$
$-x+\left(1+x^2\right) \tan ^{-1} x+C$
$x-\left(1+x^2\right) \cot ^{-1} x+C$
$-x+\left(1+x^2\right) \cot ^{-1} x+C$
$x-\left(1+x^2\right) \tan ^{-1} x+C$
$$ \int \frac{d x}{(1+\sqrt{x}) \sqrt{x-x^2}}= $$
$-2 \sqrt{\frac{1+\sqrt{x}}{1-\sqrt{x}}}+C$
$-\sqrt{\frac{1-\sqrt{x}}{1+\sqrt{x}}}+C$
$-2 \sqrt{\frac{1-\sqrt{x}}{1+\sqrt{x}}}+C$
$2 \sqrt{\frac{1+\sqrt{x}}{1-\sqrt{x}}}+C$
$$ \int \sin ^{-1}\left(\sqrt{\frac{x}{a+x}}\right) d x= $$
$(a+x) \tan ^{-1} \sqrt{\frac{x}{a}}+a x+C$
$(a+x) \tan ^{-1} \sqrt{\frac{x}{a}}+\sqrt{a x}+C$
$(a+x) \tan ^{-1} \sqrt{\frac{a}{x}}-\sqrt{a x}+C$
$(a+x) \tan ^{-1} \sqrt{\frac{x}{a}}-\sqrt{a x}+C$
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