Among the following rules, the one which is applied in the given reaction is

$$\mathrm{CH}_3 \mathrm{CHBrCH}_2 \mathrm{CH}_3 \xrightarrow{\text { Alc. } \mathrm{KOH}}$$

I. $$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_3$$ (major product)

II. $$\mathrm{CH}_2=\mathrm{CHCH}_2 \mathrm{CH}_3$$ (minor product)

Assertion (A) $$\mathrm{CH}_4$$ does not react with $$\mathrm{Cl}_2$$ in dark.

Reason (R) Chlorination of $$\mathrm{CH}_4$$ takes place in sunlight.