Center of Mass and Collision · Physics · AIIMS

A body of mass $$5 \times 10^3 \mathrm{~kg}$$ moving with speed $$2 \mathrm{~m} / \mathrm{s}$$ collides with a body of mass $$15 \times 10^3 \mathrm{~kg}$$ inelastically and sticks to it. Then loss in $$\mathrm{KE}$$ of the system will be

Assertion : There is no loss in energy in elastic collision.

Reason : Linear momentum is conserved in elastic collision.

Assertion : Even though net external force on a body is zero, momentum need not to conserved.

Reason : The internal interaction between particles of a body cancels out momentum of each other.

Body of mass M is much heavier than the other body of mass m. The heavier body with speed v collides with the lighter body which was at rest initially elastically. The speed of lighter body after collision is

Three bodies having masses $$5 \mathrm{~kg}, 4 \mathrm{~kg}$$ and $$2 \mathrm{~kg}$$ is moving at the speed of $$5 \mathrm{~m} / \mathrm{s}, 4 \mathrm{~m} / \mathrm{s}$$ and $$2 \mathrm{~m} / \mathrm{s}$$ respectively along $$X$$-axis. The magnitude of velocity of centre of mass is

Assertion Two particles moving in the same direction do not lose all their energy in completely inelastic collision.

Reason Principle of conservation of momentum holds true for all kinds of collisions.

A body of mass $$4 \mathrm{~kg}$$ moving with velocity $$12 \mathrm{~m} / \mathrm{s}$$ collides with another body of mass $$6 \mathrm{~kg}$$ at rest. If two bodies stick together after collision, then the loss of kinetic energy of system is