VITEEE 2023 | Dual Nature of Radiation Question 2 | Physics

The de-Broglie wavelength of a proton $$\left(m=1.67 \times 10^{-27} \mathrm{~kg}\right)$$ acclerated through a potential difference of $$2 \mathrm{~kV}$$ is

$$600 \mathop A\limits^o$$

$$0.636 \times 10^{-12} \mathrm{~m}$$

$$7 \mathop A\limits^o$$

$$0.63 \mathrm{~nm}$$

VITEEE 2022

MCQ (Single Correct Answer)

-0

In which of the following photoelectric effect is not observed?

Potassium

Rubidium

Magnesium

Cesium

VITEEE 2022

MCQ (Single Correct Answer)

-0

Light of wavelength $$\lambda$$ strikes a photoelectric surface and electrons are ejected with kinetic energy $$K$$. If $$K$$ is to be increased to exactly twice its original value, the wavelength must be changed to $$\lambda^{\prime}$$, such that

$$\lambda^{\prime}<\lambda / 2$$

$$\lambda^{\prime}>\lambda / 2$$

$$\lambda>\lambda^{\prime}>\frac{\lambda}{2}$$

$$\lambda^{\prime}=\frac{\lambda}{2}$$

VITEEE 2021

MCQ (Single Correct Answer)

-0

Einstein's photoelectric equation is

$$E_{\max }=h v-\phi$$

$$E=m c^2$$

$$E^2=p^2 c^2+m_0^2 c^4$$

$$E=\left(\frac{1}{2}\right) m v^2$$

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