1
VITEEE 2024
MCQ (Single Correct Answer)
+1
-0

In the following reaction the final product M will be

VITEEE 2024 Chemistry - Compounds Containing Nitrogen Question 2 English

A
VITEEE 2024 Chemistry - Compounds Containing Nitrogen Question 2 English Option 1
B
VITEEE 2024 Chemistry - Compounds Containing Nitrogen Question 2 English Option 2
C
VITEEE 2024 Chemistry - Compounds Containing Nitrogen Question 2 English Option 3
D
VITEEE 2024 Chemistry - Compounds Containing Nitrogen Question 2 English Option 4
2
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

Which of the following products is formed in the given reaction?

VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 8 English

A
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 8 English Option 1
B
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 8 English Option 2
C
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 8 English Option 3
D
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 8 English Option 4
3
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

In a set of reactions nitrobenzene gave a product $$C$$. Identify the product $$C$$.

$$\mathrm{C}_6 \mathrm{H}_5 \mathrm{NO}_2 \xrightarrow{\mathrm{Fe} / \mathrm{HCl}} A \xrightarrow[273 \mathrm{~K}]{\mathrm{NaNO}_2 / \mathrm{HCl}} B \xrightarrow[\Delta]{\mathrm{H}_2 \mathrm{O} / \mathrm{H}^{+}} C$$

A
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 7 English Option 1
B
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 7 English Option 2
C
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 7 English Option 3
D
VITEEE 2023 Chemistry - Compounds Containing Nitrogen Question 7 English Option 4
4
VITEEE 2022
MCQ (Single Correct Answer)
+1
-0

Which of the following will not give a primary amine?

A
$$\mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow{\mathrm{Br}_2, \mathrm{KOH}}$$
B
$$\mathrm{CH}_3 \mathrm{CN} \xrightarrow{\mathrm{LiAlH}_4}$$
C
$$\mathrm{CH}_3 \mathrm{NC} \xrightarrow{\mathrm{LiAlH}_4}$$
D
$$\mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow{\mathrm{LiAlH}_4}$$
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