A car of mass 500 kg is lifted by a hydraulic jack that consist of two pistons. If the diameter of large and small pistons are 2 m and 20 cm , respectively. Then force required (in N ) to lift the car by smaller piston is (take, $g=10 \mathrm{~m} / \mathrm{s}^2$ )

In a car lift, compressed air exerts a force $F_1$ on a small piston having a radius of 5.0 cm . This pressure is transmitted to a second piston of radius 15.0 cm . If the mass of the car to be lifted is 1350 kg . The force on a small piston is

With increasing temperature, the angle of contact,