Calculate the emf of the following cell:

$$\mathrm{Ni}(\mathrm{~s})+2 \mathrm{Ag}^{+}(0.01 \mathrm{M}) \rightarrow \mathrm{Ni}^{2+}(0.1 \mathrm{M})+2 \mathrm{Ag}(\mathrm{~s})$$

Given that $\mathrm{E}_{\text {cell }}^{\circ}=1.05 \mathrm{~V}, \log 10=1$