1
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

If $$(3,4,-1)$$ and $$(-1,2,3)$$ be end points of the diameter of a sphere, then the radius of the sphere is

A
2
B
3
C
6
D
7
2
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

The following lines are

$$\begin{aligned} \mathbf{r} & =(\hat{\mathbf{i}}+\hat{\mathbf{j}})+\lambda^{\prime}(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}), \\ \text { and } \quad \mathbf{r} & =(\hat{\mathbf{i}}+\hat{\mathbf{j}})+\mu(-\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}) \end{aligned}$$

A
collinear
B
skew-lines
C
coplanar lines
D
parallel lines
3
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

The position vector of a point $$R$$ which divides the line joining $$P(6,3,-2)$$ and $$Q(3,1,-4)$$ in the ratio $$2 : 1$$ externally is

A
$$\hat{\mathbf{i}}+3 \hat{\mathbf{j}}-2 \hat{\mathbf{k}}$$
B
$$3 \hat{\mathbf{i}}=\hat{\mathbf{k}}$$
C
$$-\hat{\mathbf{j}}-6 \hat{\mathbf{k}}$$
D
$$2 \hat{\mathbf{i}}-\hat{\mathbf{j}}$$
4
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

The angle between the lines $$\frac{x-5}{-3}=\frac{y+3}{-4}=\frac{z-7}{0}, \frac{x}{1}=\frac{y-1}{-2}=\frac{z-6}{2}$$ is

A
$$\frac{\pi}{3}$$
B
$$\tan ^{-1}\left(\frac{1}{5}\right)$$
C
$$\cos ^{-1}\left(\frac{1}{3}\right)$$
D
$$\frac{\pi}{2}$$
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