1
KCET 2026
MCQ (Single Correct Answer)
+1
-0
If A and B are invertible square matrices of order n, then which of the following is not correct?
A
$\det(AB) = \det(A) \cdot \det(B)$
B
$\det(kA) = k^n \det(A)$
C
$\det(A + B) = \det(A) + \det(B)$
D
$\det(A^{-1}) = \dfrac{1}{\det(A)}$
2
KCET 2026
MCQ (Single Correct Answer)
+1
-0
Which of the following is correct?
A
Determinant is a square matrix
B
Determinant is a number associated to a matrix
C
Determinant is a unique number associated to a square matrix
D
Determinant is not defined for a square matrix
3
KCET 2026
MCQ (Single Correct Answer)
+1
-0
The second order derivative of $\cos^{-1}(4x^3 - 3x)$ with respect to $\cos^{-1}(2x^2 - 1)$, where $\dfrac{1}{2} < x < 1$ is
A
$0$
B
$-\dfrac{1}{\sqrt{1 - x^2}}$
C
$\dfrac{3}{2}$
D
$-\dfrac{3}{2}$
4
KCET 2026
MCQ (Single Correct Answer)
+1
-0
$\tan^{-1}\left(\dfrac{1}{1 + 1 \cdot 2}\right) + \tan^{-1}\left(\dfrac{1}{1 + 2 \cdot 3}\right) + \ldots + \tan^{-1}\left(\dfrac{1}{1 + n(n+1)}\right) = $
A
$\tan^{-1}\left(\dfrac{n}{n+2}\right)$
B
$\tan^{-1}\left(\dfrac{n+1}{n}\right)$
C
$\tan^{-1}\left(\dfrac{n}{n+1}\right)$
D
$\tan^{-1}\left(\dfrac{n+2}{n}\right)$